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The Amplitude of a Traveling Wave on a String Is A=4mm , the Wavenumber Is K=2m^-1 , Angular Frequency Is Omega =30s^-1 . Select the

Вопрос

The amplitude of a traveling wave on a string is A=4mm , the wavenumber is k=2m^-1 , angular frequency is omega =30s^-1 . Select the correct equation of the wave . Here t is time in seconds and yis displacement in meters. ykaxute OANH BapuaHT OTBeTa y(x,t)=0.04sin(30x-2t) y(x,t)=2sin(0.04x+30t) y(x,t)=0.04sin(2x-30t) y(x,t)=30sin(4x+2t)

Решения

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Ответ

The correct equation of the wave is: Explanation:The general equation of a traveling wave on a string is given by: where: is the amplitude of the wave, is the wavenumber, is the angular frequency, and is the time.Given that the amplitude , theumber , and the angular frequency , we can substitute these values into the general equation to get the specific equation of the wave: Therefore, the correct equation of the wave is .