c) A beam of electrons moving in the positive x-direction impacts a target a vacuum chamber. If 2times 10^14 electrons traveling at a speed of 1times 10^7m strike the target during each brief pulse lasting 5times 10^-8s , Determine: (i). Porce exerted on the target during the pulse. (5marks) (iii). Pressure is exerted on the beam spot , which has radiue 4mm.

To determine the force exerted on the target during the pulse, we can use the concept of momentum transfer. The force exerted on the target is equal to the rate of change of momentum of the electrons striking the target.(i) Force exerted on the target during the pulse:Given:- Number of electrons, N = - Speed of electrons, v = - Duration of pulse, t = The force exerted on the target can be calculated using the formula:Force = where m is the mass of an electron.The mass of an electron is approximately kg.Substituting the given values, we get:Force = Simplifying the expression, we get:Force = NTherefore, the force exerted on the target during the pulse is N.(iii) Pressure exerted on the beam spot:Given:- Radius of the beam spot, r = 4 mm = mThe pressure exerted on the beam spot can be calculated using the formula:Pressure = The area of the beam spot can be calculated using the formula for the area of a circle:Area = Substituting the given values, we get:Area = Area = m²Now, substituting the force calculated earlier, we get:Pressure = Simplifying the expression, we get:Pressure = PaTherefore, the pressure exerted on the beam spot is Pa.