3. HeBsiskil B mpupautemistx koopinmar COCTABH.III: f_(x)=0,22M;f_(y)=-0,16M A6co.110THast HeBsiska paBila a) 0,24 M: b) 0,15 M: c) 0,62 M: d) 0,27 M.

Question

3. HeBsiskil B mpupautemistx koopinmar COCTABH.III: f_(x)=0,22M;f_(y)=-0,16M A6co.110THast HeBsiska paBila a) 0,24 M: b) 0,15 M: c) 0,62 M: d) 0,27 M.

Answer 1

To find the concentration of the solution, we can use the formula:

where:-

is the concentration of the solution,-

is the mass of the solute, and-

is the volume of the solution.Given that the concentration of the solution is 0.22M and the volume is 0.16M, we can substitute these values into the formula:

Simplifying the equation, we get:

Therefore, the concentration of the solution is 1.375M.

Вопрос

3. HeBsiskil B mpupautemistx koopinmar COCTABH.III: f_(x)=0,22M;f_(y)=-0,16M A6co.110THast HeBsiska paBila a) 0,24 M: b) 0,15 M: c) 0,62 M: d) 0,27 M.

Решения

Ответ