3. 3m^3 of air expands from 0.54 MPa and 45^circ C to 0.15 MP a in a polytropic process with an exponent of n=1.36 Find the final volume and temperature of the air.

To solve this problem, we can use the polytropic process equation: where:- is the initial pressure (0.54 MPa)- is the initial volume (3 m³)- is the final pressure (0.15 MPa)- is the final volume- is the polytropic exponent (1.36)First, we need to find the final volume : Substituting the given values: Next, we need to find the final temperature . We can use the relation for a polytropic process: First, we need to convert the initial temperature from Celsius to Kelvin: Now, we can find : \[ T_2 = 603.57 \text} \, the final volume of the air is 14.688 m³, and the final temperature is 603.57 K.