What amount of heat is needed to make ice weighing 150 g, taken at a temperature e of -10^circ C , get steam at 100^circ C

To calculate the amount of heat needed to make ice weighing 150 g, taken at a temperature of -10°C, get steam at 100°C, we need to consider the following steps:1. Heating the ice from -10°C to 0°C2. Melting the ice at 0°C3. Heating the water from 0°C to 100°C4. Converting the water at 100°C to steamLet's calculate the heat required for each step:1. Heating the ice from -10°C to 0°C: Q1 = m * c_ice * ΔT Q1 = 150 g * 2.09 J/g°C * (0°C - (-10°C)) Q1 = 313.5 J2. Melting the ice at 0°C: Q2 = m * L_fusion Q2 = 150 g * 334 J/g Q2 = 50100 J3. Heating the water from 0°C to 100°C: Q3 = m * c_water * ΔT Q3 = 150 g * 4.18 J/g°C * (100°C - 0°C) Q3 = 6270 J4. Converting the water at 100°C to steam: Q4 = m * L_vaporization Q4 = 150 g * 2260 J/g Q4 = 339000 JNow, let's calculate the total heat required:Q_total = Q1 + Q2 + Q3 + Q4Q_total = 313.5 J + 50100 J + 6270 J + 339000 JQ_total = 394683.5 JTherefore, the amount of heat needed to make ice weighing 150 g, taken at a temperature of -10°C, get steam at 100°C is 394683.5 J.