4. Haitru Hanmenbulee H HaH60.nbluee 3Hauenns QYHKLHHH y=f(x) Ha orpeake a;b 26 y=x^5-5x^4+5x^3+1,[-1;2]

To find the maximum and minimum values of the function on the interval , we need to find the critical points of the function within the interval and evaluate the function at the endpoints.The critical points occur where the derivative of the function is equal to zero or undefined. Let's find the derivative of the function : Now, we set the derivative equal to zero and solve for : The critical points are , , and . However, only and are within the interval .Now, we evaluate the function at the critical points and the endpoints: Therefore, the maximum value of the function on the interval is , and the minimum value is .