ovlution? or NaNO_(3) must be taken to prepare 300 ml of a 0.2M 2. For a complex compound [Ni(NH_(3))_(6)]SO_(4) indicate the outer and inner spheres, central ion, its charge and coordinate number, ligands and there dentation. Name the compound. 13. Finish and balance the redox-reaction CrCl_(3)+H_(2)O

1. To prepare a 0.2M solution of in 300 ml, you need to calculate the amount of required. The molarity (M) is defined as the number of moles of solute per liter of solution. So, you can use the formula:Molarity (M) = moles of solute / volume of solution in litersGiven that the molarity is 0.2M and the volume is 300 ml (or 0.3 liters), you can rearrange the formula to solve for the moles of solute:moles of solute = Molarity (M) x volume of solution in litersmoles of solute = 0.2M x 0.3L = 0.06 molesNow, you can calculate the mass of required using the molar mass of , which is approximately 85.0 g/mol:mass of = moles of solute x molar mass of mass of = 0.06 moles x 85.0 g/mol = 5.1 gramsTherefore, you need to take 5.1 grams of to prepare 300 ml of a 0.2M solution.2. In the complex compound , the outer sphere is the sulfate ion ( ), and the inner sphere is the nickel ion ( ) coordinated with six ammonia molecules ( ). The central ion is nickel ( ), and its charge is +2. The coordinate number is 6, as there are six ammonia molecules coordinated with the nickel ion. The ligands are the ammonia molecules ( ). The compound is named Nickel(II) hexaammine sulfate.3. To balance the redox reaction , you need to identify the oxidation states of the elements involved. In this case, chromium ( ) has an oxidation state of +3 in and +6 in . The balanced equation for the reaction is: