2. Some sample of aluminum chloride weighing 1.0000 g was dissolved in water and 250.0 ml of solution was obtained. To 10.00 ml of this solution, 20.00 ml of 0.025mol/1 EDTA solution was added. F_(0,025)=1.100 , and the resulting solution was titrated with eriochrome black T by 12.50 ml of 0.02500mol/L magnesium sulfate solution. Calculate the mass fraction of aluminum in the sample in %

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2. Some sample of aluminum chloride weighing 1.0000 g was dissolved in water and 250.0 ml of solution was obtained. To 10.00 ml of this solution, 20.00 ml of 0.025mol/1 EDTA solution was added. F_(0,025)=1.100 , and the resulting solution was titrated with eriochrome black T by 12.50 ml of 0.02500mol/L magnesium sulfate solution. Calculate the mass fraction of aluminum in the sample in %

Answer 1

To calculate the mass fraction of aluminum in the sample, we need to follow these steps:1. Calculate the concentration of EDTA in the 10.00 ml solution.2. Calculate the concentration of magnesium ions in the 10.00 ml solution.3. Calculate the concentration of aluminum ions in the 10.00 ml solution.4. Calculate the mass fraction of aluminum in the original sample.Given information:- Mass of aluminum chloride sample: 1.0000 g- Volume of solution obtained: 250.0 ml- Volume of 10.00 ml solution taken for titration: 10.00 ml- Concentration of EDTA solution: 0.025 mol/L- Titration factor (F0,025) for EDTA: 1.100- Volume of magnesium sulfate solution used for titration: 12.50 ml- Concentration of magnesium sulfate solution: 0.02500 mol/LStep 1: Calculate the concentration of EDTA in the 10.00 ml solution.Concentration of EDTA in 10.00 ml solution = (0.025 mol/L) × (10.00 ml / 250.00 ml) = 0.001 mol/LStep 2: Calculate the concentration of magnesium ions in the 10.00 ml solution.Concentration of magnesium ions in 10.00 ml solution = (0.02500 mol/L) × (12.50 ml / 250.00 ml) = 0.00125 mol/LStep 3: Calculate the concentration of aluminum ions in the 10.00 ml solution.Using the titration factor (F0,025) for EDTA, we can calculate the concentration of aluminum ions in the 10.00 ml solution.Concentration of aluminum ions in 10.00 ml solution = (0.001 mol/L) × (1.100) = 0.0011 mol/LStep 4: Calculate the mass fraction of aluminum in the original sample.Mass of aluminum in the 10.00 ml solution = (0.0011 mol/L) × (10.00 ml) × (27.00 g/mol) = 0.0297 gMass fraction of aluminum in the original sample = (0.0297 g / 1.0000 g) × 100% = 2.97%Therefore, the mass fraction of aluminum in the sample is 2.97%.

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