Dare: [ mu=29 cdot 10^-3 mathrm(kn) p=10^5 mathrm(Tla) V=3.5 cdot 10=150 mathrm(~m)^3 t=23^circ mathrm(C) m-? ]

To find the mass (m), we can use the ideal gas law equation: Where:- P is the pressure (in Pa)- V is the volume (in m³)- μ is the absolute pressure (in Pa)- R is the specific gas constant (for air, R ≈ 287 J/(kg·K))- T is the temperature (in K)First, let's convert the given values to appropriate units:- μ = 29 × 10⁻³ kN = 29 × 10³ N = 29,000 N- P = 10⁵ Tla = 10⁵ × 10¹² Pa = 10¹⁷ Pa- V = 3.5 × 10 = 150 m³- T = 23°C = 23 + 273.15 K = 296.15 KNow, we can rearrange the ideal gas law equation to solve for m: Substituting the given values: Therefore, the mass (m) is approximately 1,940 kg.