7.Two polarizers are oriented at 42.0^circ to one another .Light polarized at : 21.0^circ angle to each polarizer passes through both.What is the transmitted inten sity (0,0)[1]

To find the transmitted intensity, we can use Malus's law, which relates the intensity of light passing through a polarizer to the angle between the light's initial polarization direction and the axis of the polarizer. Malus's law is given by: where:- is the transmitted intensity,- is the initial intensity of the light,- is the angle between the light's initial polarization direction and the axis of the polarizer.In this case, the light is initially polarized at an angle of to each polarizer, and the two polarizers are oriented at to one another. To find the angle between the light's initial polarization direction and the axis of the first polarizer, we need to consider the relative angles:1. The angle between the light's initial polarization direction and the axis of the first polarizer is .2. The angle between the first polarizer and the second polarizer is .The light will pass through the first polarizer with an intensity proportional to \( \cos^2(21.0^{\circ}) \). After passing through the first polarizer, the light will be polarized along the axis of the first polarizer. The second polarizer is oriented at an angle of to the first polarizer, so the angle between the light's polarization direction and the axis of the second polarizer is .Using Malus's law, the transmitted intensity through the second polarizer is: Therefore, the transmitted intensity is: