TICKET 1-30 1. The gas mixture consists of oxygen and nitrogen and has the following composition: r_(O2)= 0.1;r_(N2)=0.9 The mixture is contained in a cylinder with a volume of 400 I, at a pressure of P_(abs)=0.9 MPa and a temperature of 27^circ C Find the mass of this mixture.

To find the mass of the gas mixture, we can use the ideal gas law equation: where:- is the pressure of the gas mixture,- is the number of moles of mixture,- is the universal gas constant,- is the temperature of the gas mixture in Kelvin.Given:- MPa = Pa- L = m³- KThe ideal gas law equation can be rearranged to solve for the number of moles ( ): Substituting the given values: Now, we can calculate the mass of the gas mixture by multiplying the number of moles by the molar mass of the gas mixture. The molar mass of the gas mixture can be calculated by taking the weighted average of the molar masses of oxygen and nitrogen, based on their respective mole fractions in the gas mixture.The molar mass of oxygen ( ) is approximately , and the molar mass of nitrogen ( ) is approximately . Finally, we can calculate the mass of the gas mixture by multiplying the number of moles by the molar mass of the gas mixture: Therefore, the mass of the gas mixture is approximately .