is for each) . How many grams of NaNO_(3) must be taken to prepare 300 ml of a 0.2M solution? For a complex compound [Ni(NH_(3))_(6)]SO_(4) indicate the outer and in spheres, central ion, its charge and coordina dentation. Name the

Question

Answer 1

To prepare a 0.2M solution of

, we need to calculate the amount of

required in grams.Given information:- Volume of the solution: 300 ml (0.3 L)- Molarity of the solution: 0.2MStep 1: Calculate the number of moles of

required.Molarity (M) = Moles of solute / Volume of solution (in liters)0.2M = Moles of

/ 0.3LMoles of

= 0.2M × 0.3L = 0.06 molesStep 2: Calculate the mass of

required.Molar mass of

= 85.0 g/molMass of

= Moles of

× Molar mass of

Mass of

= 0.06 moles × 85.0 g/mol = 5.1 gramsTherefore, to prepare 300 ml of a 0.2M solution of

, you need to take 5.1 grams of

.For the complex compound

:- Outer sphere:

- Inner sphere:

- Central ion:

- Charge: +2- Coordination: 6 (hexaammine)

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