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1) Mathrm(Fe) Stackrel(1)(arrow) Mathrm(Fe) Mathrm(Br)_(3) Stackrel(2)(arrow) Mathrm(Fe)(mathrm(OH))_(3) Stackrel(3)(arrow)

Вопрос

1) mathrm(Fe) stackrel(1)(arrow) mathrm(Fe) mathrm(Br)_(3) stackrel(2)(arrow) mathrm(Fe)(mathrm(OH))_(3) stackrel(3)(arrow) mathrm(Fe)_(2) mathrm(O)_(3) stackrel(4)(arrow) mathrm(FeO) stackrel(5)(arrow) mathrm(Fe) stackrel(6)(arrow) mathrm(Fe)_(2) mathrm(Br)_(2)

Решения

4.2 (255 Голоса)
Леонид
Экспертная проверка
элита · Репетитор 8 лет

Ответ

The given sequence of reactions represents the transformation of iron (Fe) through various compounds. Let's break down each step:1. : Iron reacts with bromine (Br2) to form iron(III) bromide (FeBr3).2. \( \mathrm{FeBr}_{3} \rightarrow \mathrm{Fe}(\mathrm{OH})_{3} \): Iron(III) bromide reacts with water (H2O) to form iron(III) hydroxide (Fe(OH)3).3. \( \mathrm{Fe}(\mathrm{OH})_{3} \rightarrow \mathrm{Fe}_{2} \mathrm{O}_{3} \): Iron(III) hydroxide decomposes upon heating to form iron(III) oxide (Fe2O3).4. : Iron(III) oxide reacts with carbon monoxide (CO) to form iron(II) oxide (FeO).5. : Iron(II) oxide reacts with carbon dioxide (CO2) to form iron (Fe).6. : Iron reacts with bromine (Br2) to form iron(II) bromide (Fe2Br2).Therefore, the correct answer is: .