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1) Dane [ Gamma_(4)=6 (mathrm(k))/(mathrm(c)) Gamma_(2)=2 (mathrm(k))/(mathrm(c)) M_(4)=40 Mathrm(k) (m_(2)=20 Mathrm(~m))/(x_(x)-?) ]

Вопрос

1) Dane [ gamma_(4)=6 (mathrm(k))/(mathrm(c)) gamma_(2)=2 (mathrm(k))/(mathrm(c)) m_(4)=40 mathrm(k) (m_(2)=20 mathrm(~m))/(x_(x)-?) ]

Решения

4.5 (232 Голоса)
Константин
Экспертная проверка
эксперт · Репетитор 3 лет

Ответ

It seems like there might be a typo in the last line of the provided data. Let's correct it and proceed with the calculations.Given: To find , we need to understand the relationship between these variables. Assuming is the acceleration, we can use Newton's second law: For object 4: For object 2: Since the forces are equal (assuming no external forces acting on the system): Thus, the acceleration is the same for both objects: So, the value of is .