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0.02_(KT)cdot 9.8M/c^2cdot 4Mcdot Sin(30^circ )=(1)/(rho )

Вопрос

0.02_(KT)cdot 9.8M/c^2cdot 4Mcdot sin(30^circ )=(1)/(rho )

Решения

4.2 (201 Голоса)
Умар
Экспертная проверка
профессионал · Репетитор 6 лет

Ответ

To solve the given equation, we need to find the value of ρ (rho).Given equation: First, let's simplify the equation step by step:1. Convert to (assuming it's a typo and should be ).2. Calculate , which is .3. Multiply the constants together: .Now, let's perform the calculations: So, the equation becomes: To find ρ, we take the reciprocal of both sides: Now, let's calculate the value of ρ: Therefore, the value of ρ is approximately .