A periodic simple harmonic oscillator is given by: y=3sin(pi t) meters , where t is in seconds The period of the system is: a. 2s b. 0.5 s c. 2 Hz d. 3 m

The correct answer is a. 2s.In a simple harmonic oscillator, the period (T) is the time it takes for the system to complete one full cycle of motion. In the given equation, y = 3sin(πt), the argument of the sine function is πt. The period is the time it takes for the argument to increase by 2π, which is the period of the sine function.To find the period, we can set the argument equal to 2π and solve for t:πt = 2πt = 2Therefore, the period of the system is 2 seconds.