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3. Weighed Quantity of Metallic Magnesium (0 .0800 G) Was Dissolved in Sulfuric Acid, and Then Was Titrated By10.15 Ml of EDTA Solution

Вопрос

3. Weighed quantity of metallic magnesium (0 .0800 g) was dissolved in sulfuric acid, and then was titrated by10.15 ml of EDTA solution in the presence of an ammonia buffer . Calculate the titer of the EDTA solution

Решения

4.2 (184 Голоса)
Ольга
Экспертная проверка
элита · Репетитор 8 лет

Ответ

To calculate the titer of the EDTA solution, we need to determine the concentration of the EDTA solution using the weighed quantity of metallic magnesium and the volume of EDTA solution used in the titration.Given information:- Weighed quantity of metallic magnesium: 0.0800 g- Volume of EDTA solution used in the titration: 10.15 mLStep 1: Calculate the moles of metallic magnesium.Moles of metallic magnesium = Mass of metallic magnesium / Molar mass of metallic magnesiumMolar mass of metallic magnesium = 24.305 g/molMoles of metallic magnesium = 0.0800 g / 24.305 g/mol = 0.00328 molStep 2: Calculate the concentration of the EDTA solution.Moles of EDTA = Moles of metallic magnesium (since the reaction is 1:1)Volume of EDTA solution = 10.15 mL = 0.01015 LConcentration of EDTA solution = Moles of EDTA / Volume of EDTA solutionConcentration of EDTA solution = 0.00328 mol / 0.01015 L = 0.323 MTherefore, the titer of the EDTA solution is 0.323 M.