A force of F=3N was acting on a point particle that has moved for S=0.5m In the direction of force. What is the work A done by the force? Please select one answer option A=3.5J A=1.5J A=4.5J A=6J

To calculate the work done by the force, we can use the formula:Work = Force x Displacement x cos(θ)where:- Force is the magnitude of the force acting on the particle- Displacement is the distance the particle has moved in the direction of the force- θ is the angle between the force and the displacementIn this case, the force is acting in the same direction as the displacement, so the angle θ is 0 degrees. The cosine of 0 degrees is 1.Substituting the given values into the formula:Work = 3 N x 0.5 m x cos(0°)Work = 3 N x 0.5 m x 1Work = 1.5 JTherefore, the correct answer is: