6. 0.5000 g of sodium chloride was dissolved in water and 200.0 ml of the solution was obtained. 20 .00 ml of this solution was titrated with 15.84 ml of silver nitrate solution . Calculate the molar concentration of the titrant solution.

Question

6. 0.5000 g of sodium chloride was dissolved in water and 200.0 ml of the solution was obtained. 20 .00 ml of this solution was titrated with 15.84 ml of silver nitrate solution . Calculate the molar concentration of the titrant solution.

Answer 1

To calculate the molar concentration of the titrant solution, we need to follow these steps:1. Calculate the moles of sodium chloride (NaCl) in the 20.00 ml solution.2. Use the stoichiometry of the reaction between NaCl and silver nitrate (AgNO3) to find the moles of AgNO3.3. Calculate the molar concentration of the AgNO3 solution.Step 1: Calculate the moles of NaCl in the 20.00 ml solution.Moles of NaCl = (mass of NaCl) / (molar mass of NaCl)Moles of NaCl = 0.5000 g / (58.44 g/mol)Moles of NaCl = 0.00857 molStep 2: Use the stoichiometry of the reaction between NaCl and AgNO3 to find the moles of AgNO3.The balanced chemical equation for the reaction between NaCl and AgNO3 is:NaCl + AgNO3 → AgCl + NaNO3From the equation, we can see that 1 mole of NaCl reacts with 1 mole of AgNO3.Therefore, the moles of AgNO3 = moles of NaClMoles of AgNO3 = 0.00857 molStep 3: Calculate the molar concentration of the AgNO3 solution.Molar concentration = moles of solute / volume of solution in litersMolar concentration = 0.00857 mol / 0.020 LMolar concentration = 0.429 mol/LTherefore, the molar concentration of the titrant solution (silver nitrate solution) is 0.429 mol/L.

Вопрос

6. 0.5000 g of sodium chloride was dissolved in water and 200.0 ml of the solution was obtained. 20 .00 ml of this solution was titrated with 15.84 ml of silver nitrate solution . Calculate the molar concentration of the titrant solution.

Решения

Ответ