Вопрос
1. What mass (g) of sulfuric acid must be taken to prepare 250 ml of 2 N solution? 2. For a complex compound [Cu(NH_(3))_(4)]Cl_(2) indicate the outer and inner spheres, central ion, its charge and coordinate number, ligands and there dentation. Name the compound. 3. Finish and balance the redox-reaction MnSO_(4)+NaBiO_(3)+HNO_(3)= 4. Calculate the mass of Ag^+ in 0.1 M solution of diamine silver chloride containing an excess of 1 mole of NH_(3)cdot (K_(inst)=9.3cdot 10^-8) Evnlain if FeCl_(2) can be oxidized by H_(2)O_(2) in acidic media?
Решения
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Ответ
1. To prepare a 2 N solution of sulfuric acid (H2SO4) in 250 ml, you need to calculate the mass of H2SO4 required. Normality (N) is defined as the number of equivalents of solute per liter of solution. For H2SO4, the equivalent weight is 49.04 g/mol (since it provides 2 H+ ions per molecule). Therefore, the mass of H2SO4 needed is:
So, 24.52 grams of sulfuric acid must be taken to prepare 250 ml of a 2 N solution.2. For the complex compound
:- Outer sphere:
and
- Inner sphere:
- Central ion: Cu- Charge: +2- Coordinate number: 4- Ligands: NH3- Dentation: TetrahedralThe compound is named Tetrakis(ammine)copper(II) chloride.3. The balanced redox reaction between
and
in the presence of
is:
4. To calculate the mass of
in a 0.1 M solution of diamine silver chloride (
) containing an excess of 1 mole of
, we need to consider the solubility product constant (
) for
.The solubility product constant for
is
.The dissociation of
in water can be represented as:
Given that the concentration of
is in excess, the concentration of
will be equal to the concentration of
.Let the concentration of
be
. Then, the concentration of
will also be
.The solubility product constant expression for
is:
Now, to find the mass of
, we multiply the concentration by the molar mass of
:
So, the mass of
in the solution is
grams.Regarding the oxidation of
by
in acidic media, we need to consider the standard reduction potentials of the involved species. The standard reduction potential for
is +0.77 V, while for
it is +1.77 V. Since the reduction potential of
is higher than that of
,