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2log_(1x^3)-8x+17vert 2:(3x^2+5)leqslant Log_(3)3-8x+17:2x^2+7x+5}

Вопрос

2log_(1x^3)-8x+17vert 2:(3x^2+5)leqslant log_(3)3-8x+17:2x^2+7x+5}

Решения

4.2 (212 Голоса)
Юлий
Экспертная проверка
ветеран · Репетитор 10 лет

Ответ

To solve the given inequality, we need to simplify and analyze each part of the expression.First, let's simplify the expression inside the absolute value: Since is not a valid logarithm (the base must be positive and not equal to 1), we cannot simplify this part further.Next, let's simplify the expression inside the parentheses: Since , we can rewrite the inequality as: Simplifying the right side, we get: Rearranging the terms, we have: Now, let's solve the quadratic inequality: Using the quadratic formula, we find the roots of the equation: So, the solutions to the quadratic equation are: and Now, let's consider the absolute value expression: Since is not valid, we cannot solve this inequality.Therefore, the given inequality cannot be solved due to the invalid logarithmic expression.