24. Hpa rpagpa, saqamioro: a) Marpunjei cMexHOCTIA A = A=(} 0&1&0&0&0 1&0&2&0&1 0&2&0&0&1 0&0&0&0&0 0&1&1&0&1 ) 6) Marpuneii mungnewrrnocm B = B=(} -1&0&0&0&0&1 1&3&-1&-1&0&0 0&0&1&0&1&0 0&0&0&1&-1&0 0&0&0&0&0&-1 ) 3amunurre Marpsuy CMEXHOCTI WIN MULTIPHTHOCTH, onpenenmer

Question

24. Hpa rpagpa, saqamioro: a) Marpunjei cMexHOCTIA A = A=(} 0&1&0&0&0 1&0&2&0&1 0&2&0&0&1 0&0&0&0&0 0&1&1&0&1 ) 6) Marpuneii mungnewrrnocm B = B=(} -1&0&0&0&0&1 1&3&-1&-1&0&0 0&0&1&0&1&0 0&0&0&1&-1&0 0&0&0&0&0&-1 ) 3amunurre Marpsuy CMEXHOCTI WIN MULTIPHTHOCTH, onpenenmer

Answer 1

To determine whether the given matrices A and B are multiplicative inverses, we need to check if their product is the identity matrix.The identity matrix is a square matrix with ones on the diagonal and zeros elsewhere. In this case, both matrices A and B are 6x5 matrices, so they cannot be multiplicative inverses.Therefore, the correct answer is: Neither A nor B is the multiplicative inverse of the other.

Вопрос

24. Hpa rpagpa, saqamioro: a) Marpunjei cMexHOCTIA A = A=(} 0&1&0&0&0 1&0&2&0&1 0&2&0&0&1 0&0&0&0&0 0&1&1&0&1 ) 6) Marpuneii mungnewrrnocm B = B=(} -1&0&0&0&0&1 1&3&-1&-1&0&0 0&0&1&0&1&0 0&0&0&1&-1&0 0&0&0&0&0&-1 ) 3amunurre Marpsuy CMEXHOCTI WIN MULTIPHTHOCTH, onpenenmer

Решения

Ответ