Вопрос
1) An enzyme that catalyzes the transformation of one substrate is characterized by the following specificity: a)absolute: b) relative; c) stereospecificity; d)allosteric: e) group. 2) Most food and microbial enzymes are destroyed at {}^circ C a) 15 b) 25 c) 37 d) 80 3) Regulation of enzyme activity cannot be carried out by: a) covalent chemical modification; b) formation of a substrate-substrate complex; c) allosteric regulation; d) partial proteolysis. 4) The division of enzymes into classes is based on: a) substrate structure b) structure of coenzymes c) structure of reaction products d) type of catalyzed reaction 5) The Michaelis-Menten equation. If for Enzyme "A" Vmax equals to 100mu mol/mL sec and Km equals to 2 mM, what is the velocity of the reaction when substrate "B"concentration equals to 20 mM?
Решения
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Светлана
Экспертная проверка
профессионал · Репетитор 6 лет
Ответ
1) An enzyme that catalyzes the transformation of one substrate is characterized by the following specificity:a) absolute: This is the correct answer. Absolute specificity refers to an enzyme that catalyzes the transformation of only one substrate.2) Most food and microbial enzymes are destroyed at
c) 37: This is the correct answer. Most food and microbial enzymes are destroyed at 37°C, which is the optimal temperature for the growth of many microorganisms.3) Regulation of enzyme activity cannot be carried out by:b) formation of a substrate-substrate complex: This is the correct answer. The formation of a substrate-substrate complex is not a method of regulating enzyme activity.4) The division of enzymes into classes is based on:d) type of catalyzed reaction: This is the correct answer. Enzymes are divided into classes based on the type of reaction they catalyze.5) The Michaelis-Menten equation. If for Enzyme "A" Vmax equals to
sec and Km equals to 2 mM, what is the velocity of the reaction when substrate "B" concentration equals to 20 mM?To solve this question, we can use the Michaelis-Menten equation:V = (Vmax \* [S]) / (Km + [S])where V is the velocity of the reaction, Vmax is the maximum velocity, [S] is the substrate concentration, and Km is the Michaelis constant.Given that Vmax = 100 μmol/mL sec and Km = 2 mM, we can substitute these values into the equation:V = (100 μmol/mL sec \* 20 mM) / (2 mM + 20 mM)V = 2000 μmol/mL sec / 22 mMV ≈ 90.91 μmol/mL secTherefore, the velocity of the reaction when the substrate "B" concentration equals to 20 mM is approximately 90.91 μmol/mL sec.