Вопрос
5) How much heat can be produced from a reaction mixture of 50 gof iron (III) oxide and 25 g of aluminium in the thermite reaction: Fe_(2)O_(3)(s)+2Al(s)arrow Al_(2)O_(3)(s)+2Fe(s);Delta H=-851.5kJ/m
Решения
4.1
(173 Голоса)
Федора
продвинутый · Репетитор 1 лет
Ответ
To calculate the amount of heat produced in the thermite reaction, we need to determine the limiting reactant and then use the given enthalpy change to find the heat released.First, let's calculate the moles of iron(III) oxide (Fe2O3) and aluminum (Al):Moles of Fe2O3 = mass / molar mass = 50 g / 159.69 g/mol = 0.314 molMoles of Al = mass / molar mass = 25 g / 26.98 g/mol = 0.923 molNext, we need to determine the stoichiometric ratio between Fe2O3 and Al in the balanced chemical equation:Fe2O3(s) + 2Al(s) → Al2O3(s) + 2Fe(s)From the balanced equation, we can see that 1 mole of Fe2O3 reacts with 2 moles of Al. Therefore, the stoichiometric ratio is 1:2.Now, let's compare the moles of Fe2O3 and Al to the stoichiometric ratio:Moles of Fe2O3 / 1 = 0.314 molMoles of Al / 2 = 0.923 mol / 2 = 0.462 molSince the moles of Al are greater than the moles of Fe2O3, Al is the excess reactant, and Fe2O3 is the limiting reactant.Now, we can calculate the heat produced using the given enthalpy change:Heat produced = Moles of limiting reactant × Enthalpy changeHeat produced = 0.314 mol × (-851.5 kJ/mol)Heat produced = -268.6 kJTherefore, the reaction mixture can produce approximately 268.6 kJ of heat.