Hañ AHTe 39cos((7pi )/(2)+alpha ) , ecjin cosalpha =-(5)/(13)H alpha in (0,5pi ;pi )

Question

Answer 1

To solve the given expression, we need to find the value of

in the interval

such that

.First, let's simplify the expression

:

Now, we have

, which simplifies to

.Since

is in the interval

, we know that

is in the third quadrant where sine is negative. Therefore,

.Now, we can use the Pythagorean identity

to find the value of

:

Since

is in the third quadrant where cosine is negative, we have

.Therefore, the value of

in the interval

such that

is

.

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