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Sqrt (((0.049)/(54.912))^2+((0.020)/(1.00))^2+((2times 0.036)/(5.09))^2)

Вопрос

sqrt (((0.049)/(54.912))^2+((0.020)/(1.00))^2+((2times 0.036)/(5.09))^2)

Решения

4.6 (253 Голоса)
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мастер · Репетитор 5 лет

Ответ

To solve the given expression, we need to calculate the square root of the sum of the squares of the fractions.Let's break down the expression step by step:1. Calculate the numerator and denominator of each fraction separately: - - - 2. Square each fraction: - - - 3. Add the squared fractions together: - 4. Finally, take the square root of the sum: - Now, let's calculate the values:1. 2. 3. Squaring these values:1. )^2 = 0.0004 (0.0142)^2 \approx 0.00020164 0.000000789 + 0.0004 + 0.00020164 \approx 0.000602429 \sqrt{0.000602429} \approx 0.0245$Therefore, the value of the given expression is approximately 0.0245.