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The Mixture Consists of 0.05 Mol of Sodium Hy- Droxide Na and 7.525 -11024 Molecules of Water. Determine the Mass of the Mixture.

Вопрос

The mixture consists of 0.05 mol of sodium hy- droxide Na and 7.525 -11024 molecules of water. Determine the mass of the mixture.

Решения

4.1 (186 Голоса)
Галина
Экспертная проверка
элита · Репетитор 8 лет

Ответ

To determine the mass of the mixture, we need to calculate the mass of sodium hydroxide (NaOH) and the mass of water (H2O) separately, and then add them together.Given information:- The mixture consists of 0.05 mol of sodium hydroxide (NaOH).- The mixture consists of 7.525 × 10^22 molecules of water.Step 1: Calculate the mass of sodium hydroxide (NaOH).Molar mass of NaOH = 40.00 g/molMass of NaOH = Number of moles × Molar massMass of NaOH = 0.05 mol × 40.00 g/mol = 2.00 gStep 2: Calculate the mass of water (H2O).Number of molecules of water = 7.525 × 10^22Molar mass of H2O = 18.02 g/molMass of H2O = Number of molecules × Molar mass / Avogadro's numberMass of H2O = (7.525 × 10^22) × (18.02 g/mol) / (6.022 × 10^23 molecules/mol) = 27.00 gStep 3: Calculate the total mass of the mixture.Total mass of the mixture = Mass of NaOH + Mass of H2OTotal mass of the mixture = 2.00 g + 27.00 g = 29.00 gTherefore, the mass of the mixture is 29.00 g.