BapnaHT 26. B) lim _(xarrow -8)(3x+24)/(sin(2x+16))

To find the limit of the given expression as approaches , we can use the fact that \(\sin(2x+16)\) approaches 0 as approaches . We can rewrite the expression as: As approaches , the numerator approaches 0, and the denominator \(\sin(2x+16)\) approaches 0. This is an indeterminate form of type , so we can apply L'Hôpital's Rule.Taking the derivative of the numerator and denominator with respect to , we get: Now, as approaches , the denominator \(\cos(2x+16)\) approaches \(\cos(0)\), which is 1. Therefore, the limit is: So, the correct answer is .