12-1. The intensity of a sound produced by a point source decreases as the square of the distance from the source. Consider a riveter as a point source of sound and assume that the intensities listed in Table are measured at a distance Im away from the source . What is the maximum distance at which the riveter is still audible? (Neglect losses due to energy absorption in the air.) 12-2. Referring to Table , approximately how much louder does busy street traffic sound than a quiet radio? 12-3.Calculate the pressure variation corresponding to a sound intensity of 10^-16W/cm^2. (The density of air at 0^circ C and 1 atm pressure is 1.29times 10^-3g/cm^3 for the speed of sound use the value 3.3times 10^4cm/sec.

12-1. The intensity of a sound produced by a point source decreases as the square of the distance from the source. Consider a riveter as a point source of sound and assume that the intensities listed in Table are measured at a distance Im away from the source. What is the maximum distance at which the riveter is still audible? (Neglect losses due to energy absorption in the air.)To find the maximum distance at which the riveter is still audible, we need to determine the intensity level at which sound becomes inaudible. Typically, the threshold of hearing is around 0 dB. Assuming the intensity of the riveter at a distance Im is given in the table, we can use the inverse square law to find the maximum distance.The inverse square law states that the intensity of a sound is inversely proportional to the square of the distance from the source. Mathematically, this can be expressed as:I = k / r^2where I is the intensity, k is a constant, and r is the distance from the source.Given that the intensity of the riveter at a distance Im is known, we can rearrange the equation to solve for the maximum distance at which the riveter is still audible:r_max = sqrt(k / I)By substituting the given intensity value from the table into the equation, we can calculate the maximum distance at which the riveter is still audible.12-2. Referring to Table, approximately how much louder does busy street traffic sound than a quiet radio?To determine how much louder busy street traffic sounds compared to a quiet radio, we need to compare their respective intensity levels. The intensity level of a sound is measured in decibels (dB), which is a logarithmic scale.The decibel scale is defined as:L = 10 * log10(I / I_0)where L is the intensity level in decibels, I is the intensity of the sound, and I_0 is the reference intensity, typically taken as the threshold of hearing (0 dB).By comparing the intensity levels of busy street traffic and a quiet radio from the table, we can calculate the difference in decibels using the formula:ΔL = L_traffic - L_radiowhere ΔL represents the difference in intensity levels between busy street traffic and a quiet radio.12-3. Calculate the pressure variation corresponding to a sound intensity of (The density of air at and 1 atm pressure is for the speed of sound use the value To calculate the pressure variation corresponding to a given sound intensity, we can use the relationship between pressure and intensity:P = sqrt(2 * I * ρ * c^2)where P is the pressure variation, I is the sound intensity, ρ is the density of the medium, and c is the speed of sound.Given the sound intensity of , the density of air at and 1 atm pressure as , and the speed of sound as , we can substitute these values into the equation to calculate the pressure variation:P = sqrt(2 * * * ( )^2)By performing the calculation, we can determine the pressure variation corresponding to the given sound intensity.