Вопрос
10. A weighed portion of the alloy (2.1574 g) was dissolved and,, after appropriat C. livati the volume of the solution was adjusted to 100.0 ml the percentage of silver in the alloy, if the following results were obtained during potentiometric titration of 25 ml of the prepared solution of 0.1250 N NaCl: 16 18 20.5 V,ml E.V 0.689 0.670 0.652 0.634 +0.594 0.5180.441 0.4010 .383 obtained during
Решения
4.2
(166 Голоса)
Ирина
профессионал · Репетитор 6 лет
Ответ
To determine the percentage of silver in the alloy, we need to follow these steps:1. Calculate the moles of NaCl used in the titration.2. Determine the moles of silver in the alloy.3. Calculate the percentage of silver in the alloy.Given:- Volume of the alloy solution: 25 mL- Normality of NaCl solution: 0.01250 N- Volume of NaCl solution used in titration: 16 mLStep 1: Calculate the moles of NaCl used in the titration.Moles of NaCl = Normality × Volume (in liters)Moles of NaCl = 0.01250 N × 0.016 L = 0.0002 molesStep 2: Determine the moles of silver in the alloy.Since the reaction between NaCl and silver is a 1:1 molar ratio, the moles of silver in the alloy will be equal to the moles of NaCl used in the titration.Moles of silver = 0.0002 molesStep 3: Calculate the percentage of silver in the alloy.Percentage of silver = (Moles of silver / Moles of alloy) × 100%Percentage of silver = (0.0002 moles / (0.0002 moles / 25 mL)) × 100% = 2.5%Therefore, the percentage of silver in the alloy is 2.5%.