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2. The Pipe with an Outer Diameter of D=35mm Is Cooled in an Oil Cross Flow (oil Is Trans.oil). The Oil Flow Velocity and the Average

Вопрос

2. The pipe with an outer diameter of d=35mm is cooled in an oil cross flow (oil is trans.oil). The oil flow velocity and the average oil temperature are respectively: w =0.5m/s and t_(1)=25^circ C Determine what temperature of the pips surface must be maintained so that the heat flux will be equal to q=30W/m^2 and what will be the value of the heat transfer coefficient?

Решения

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профессионал · Репетитор 6 лет

Ответ

To determine the temperature of the pipe's surface that must be maintained so that the heat flux will be equal to , we can use the formula for heat transfer by conduction: where:- is the heat flux (in )- is the heat transfer coefficient (in )- is the average oil temperature (in )- is the temperature of the pipe's surface (in )We need to find , so we rearrange the formula: To find the value of the heat transfer coefficient, we can use the convection heat transfer equation: where:- is the Nusselt number (dimensionless)- is the convective heat transfer coefficient (in )For turbulent flow, the Nusselt number can be estimated using the Dittus-Boelter equation: where:- is the Reynolds number- is the Prandtl numberThe Reynolds number can be calculated as: where:- is the oil flow velocity (in )- is the outer diameter of the pipe (in )- is the kinematic viscosity of the oil (in )The Prandtl number can be estimated as: where:- is the thermal diffusivity of the oil (in )Assuming typical values for oil, let's take and .First, calculate the Reynolds number: Next, calculate the Prandtl number: Now, calculate the Nusselt number: Finally, calculate the heat transfer coefficient: Now, we can find the temperature of the pipe's surface: So, the temperature of the pipe's surface must be maintained at approximately to achieve a heat flux of , and the value of the heat transfer coefficient is approximately .