Вопрос
2. The pipe with an outer diameter of d=35mm is cooled in an oil cross flow (oil is trans.oil). The oil flow velocity and the average oil temperature are respectively: w =0.5m/s and t_(1)=25^circ C Determine what temperature of the pips surface must be maintained so that the heat flux will be equal to q=30W/m^2 and what will be the value of the heat transfer coefficient?
Решения
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профессионал · Репетитор 6 лет
Ответ
To determine the temperature of the pipe's surface that must be maintained so that the heat flux will be equal to
, we can use the formula for heat transfer by conduction:
where:-
is the heat flux (in
)-
is the heat transfer coefficient (in
)-
is the average oil temperature (in
)-
is the temperature of the pipe's surface (in
)We need to find
, so we rearrange the formula:
To find the value of the heat transfer coefficient, we can use the convection heat transfer equation:
where:-
is the Nusselt number (dimensionless)-
is the convective heat transfer coefficient (in
)For turbulent flow, the Nusselt number can be estimated using the Dittus-Boelter equation:
where:-
is the Reynolds number-
is the Prandtl numberThe Reynolds number can be calculated as:
where:-
is the oil flow velocity (in
)-
is the outer diameter of the pipe (in
)-
is the kinematic viscosity of the oil (in
)The Prandtl number can be estimated as:
where:-
is the thermal diffusivity of the oil (in
)Assuming typical values for oil, let's take
and
.First, calculate the Reynolds number:
Next, calculate the Prandtl number:
Now, calculate the Nusselt number:
Finally, calculate the heat transfer coefficient:
Now, we can find the temperature of the pipe's surface:
So, the temperature of the pipe's surface must be maintained at approximately
to achieve a heat flux of
, and the value of the heat transfer coefficient is approximately
.