B2. What velocity D will an initially resting hydrogen atom acquire when emitting a photon corresponding to the first line of the Lyman series. ( h=6,62cdot 10^-34L_(K)cdot c,m_(H)=1,66cdot 10^-27kr,R=3,3cdot 10^15c^-1 (lambda =600nm) is incident on a thin glass wedge normal faces of the wedge if the liaht is

To find the velocity that a hydrogen atom will acquire when emitting a photon corresponding to the first line of the Lyman series, we need to use the principles of energy conservation and the relationship between photon energy and momentum.The energy of the photon is given by: The momentum of the photon is given by: The energy of the hydrogen atom before emitting the photon is essentially zero (since it is initially at rest). After emitting the photon, the hydrogen atom will have a kinetic energy given by: Since energy is conserved, the energy of the photon will be equal to the kinetic energy of the hydrogen atom: We can solve for the velocity (which we'll denote as in the question): Now, let's plug in the given values:- - - - Therefore, the velocity that the hydrogen atom will acquire when emitting a photon corresponding to the first line of the Lyman series is approximately .