Вопрос
In the experiment , the motion of a body was investig ated, a s a result of which the average speed and its absolute error were obtained bar (V)=25.6m/s Delta bar (V)=0.1648025ldots m/s Please indicate the correct record of the final result of this experiment. V=(25.6+0.1)m/s V=(25.6pm 0.2)m/s V=(25.60pm 0.1)m/s V=(25.6pm 0.1)m/s
Решения
4.1
(229 Голоса)
Даниэль
Экспертная проверка
мастер · Репетитор 5 лет
Ответ
The correct record of the final result of this experiment is:
Explanation:The average speed is given as
, and the absolute error is given as
. To record the final result, we need to round the absolute error to the appropriate number of significant figures.Since the average speed is given to two decimal places, we should round the absolute error to two decimal places as well. Therefore, the absolute error is rounded to
.The final result is recorded as
, where the average speed is given to two decimal places and the absolute error is given to two decimal places as well.