1. How many grams of NaNO_(3) must be taken to prepare 300 ml of a 0.2N solution? 2. For a complex compound [Ni(NH_(3))_(6)]SO_(4) indicate the outer and inner spheres, central ion, its charge and coordinate number, ligands and there dentation. Name the compound.

Question

1. How many grams of NaNO_(3) must be taken to prepare 300 ml of a 0.2N solution? 2. For a complex compound [Ni(NH_(3))_(6)]SO_(4) indicate the outer and inner spheres, central ion, its charge and coordinate number, ligands and there dentation. Name the compound.

Answer 1

1. To prepare a 0.2N solution of NaNO3, we need to calculate the amount of NaNO3 required.Normality (N) is defined as the number of equivalents of solute per liter of solution. In this case,ity is 0.2N, which means there are 0.2 equivalents of NaNO3 per liter of solution.To find the amount of NaNO3 required, we can use the formula:Amount of solute (in grams) = Normality (N) x Volume (in liters) x Molar mass (in g/mol)Given:Normality (N) = 0.2NVolume (V) = 300 mL = 0.3 LMolar mass of NaNO3 = 85.0 g/molSubstituting the values into the formula:Amount of NaNO3 = 0.2N x 0.3 L x 85.0 g/molAmount of NaNO3 = 5.1 gramsTherefore, of NaNO3 must be taken to prepare 300 mL of a 0.2N solution.2. For the complex compound [Ni(NH3)6]SO4:Outer sphere: [Ni(NH3)6]^2+Inner sphere: SO4^2-Central ion: Ni^2+Charge: +2Coordinate number: 6Ligands: NH3 (ammonia)The compound is named as Nickel(II) hexaammine sulfate.

Вопрос

1. How many grams of NaNO_(3) must be taken to prepare 300 ml of a 0.2N solution? 2. For a complex compound [Ni(NH_(3))_(6)]SO_(4) indicate the outer and inner spheres, central ion, its charge and coordinate number, ligands and there dentation. Name the compound.

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