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Standard Conditions: Temperature -0^circ C Pressure -101.325kPa Example 4. At 25^circ C and a Pressure of 99.3 KPa (745 MmHg) a Certain

Вопрос

Standard conditions: Temperature -0^circ C Pressure -101.325kPa Example 4. At 25^circ C and a pressure of 99.3 kPa (745 mmHg) a certain amount of a gas occupies a volume of .152 ml. Calculat the volume that the same amount of the gas will occupy at 0^circ C anc 1. a pressure of 101.33 kPa. 32.The pressure of bar (a) gas in a closed vessel is 96.0 kPa at 7^circ C . What will the pressure be if the vessel is cooled to 2. -33^circ C 33. In standard conditions, 1 g of air occupies a volume of 773 ml. What volume will the same mass of air occupy 3. at 0^circ C and a pressure of 93.3kPa(700mmHg) __ 37. A certain amount of a gas occupies a volume of 608 ml at a pressure of 98 .7 kPa and a temperature of 91^circ C . Find "57.What I __ volume is occupied by 27times 10^21 molecules of a 5.gas in standard conditions? __ 63. Determine e the volume occupied by 0.07 kg of N_(s) at 6. 24^circ C and 142 kPa (1065 mmHg).

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мастер · Репетитор 5 лет

Ответ

Let's go through each problem step by step:### Example 4Given:- Initial temperature, - Initial pressure, - Initial volume, - Final temperature, - Final pressure, Using the combined gas law: Solving for : ### Problem 32Given:- Initial pressure, - Initial temperature, - Final temperature, Using Charles's Law: Solving for : ### Problem 33Given:- Mass of air, - Volume at standard conditions, - Standard pressure, - Final temperature, - Final pressure, Using the combined gas law: Solving for : ### Problem 37Given:- Initial volume, - Initial pressure, - Initial temperature, - Final temperature, Using Charles's Law: Solving for : ### Problem 57Given:- Number of molecules, - Standard pressure, - Standard temperature, - Avogadro's number, Using the ideal gas law: First, find the number of moles: Now, find the volume: \[ V = \frac{4.49 \times 10^{-2} \times 8.314 \times 273.15