6. In the district of 500000 population 10 persons affected by achondroplasia (autosomal dominant disease) live. Define a number of heterozygous carriers in the population.

To solve this problem, we can use the Hardy-Weinberg equilibrium equation, which is a mathematical equation that describes the genetic variation in a population at equilibrium. The equation is:p^2 + 2pq + q^2 = 1where p is the frequency of the dominant allele (in this case, the allele for achondroplasia), q is the frequency of the recessive allele, and 2pq is the frequency of heterozygous carriers.In this case, we know that there are 10 affected individuals (homozygous dominant) in a population of 500,000. We can use this information to calculate the frequency of the dominant allele (p) as follows:p^2 = 10/500,000p = sqrt(10/500,000)p ≈ 0.0019Now, we can use the Hardy-Weinberg equation to calculate the frequency of heterozygous carriers (2pq):2pq = 2 * 0.0019 * (1 - 0.0019)2pq ≈ 0.0036To find the number of heterozygous carriers in the population, we can multiply the frequency of heterozygous carriers by the total population:Number of heterozygous carriers = 0.0036 * 500,000Number of heterozygous carriers ≈ 1,800Therefore, there are approximately 1,800 heterozygous carriers of achondroplasia in the population.