Date: [ t_(1)=0^circ mathrm(C) ] [ P_(1)=10^59 mathrm(~kg) ] [ V= ( const ) ] [ Delta P=3 cdot 10^5 mathrm(~m) ] 4) P= ? (P_(2))/(P_(1))= ? 6) T_(2)= ?

Question

Date: [ t_(1)=0^circ mathrm(C) ] [ P_(1)=10^59 mathrm(~kg) ] [ V= ( const ) ] [ Delta P=3 cdot 10^5 mathrm(~m) ] 4) P= ? (P_(2))/(P_(1))= ? 6) T_(2)= ?

Answer 1

To solve this problem, we can use the ideal gas law, which states that the pressure of a gas is directly proportional to its temperature, provided the volume remains constant.Given:

We need to find:

Step 1: Convert the temperature from Celsius to Kelvin.

Step 2: Use the ideal gas law to find the pressure.Since the volume is constant, we can use the formula

.Step 3: Substitute the given values into the formula.

Step 4: Solve for

.

Step 5: Calculate the value of

using the given

.

Step 6: Substitute the value of

into the equation from Step 4.

Step 7: Solve for

.\( T_{2} = \frac{(10^{59} + 3 \cdot 10^{5}) \cdot 273.15}{10^{59}} \)Step 8: Calculate the value of

.

Step 9: Calculate the value of

.

Step 10: Calculate the value of

.

Answer:

Вопрос

Date: [ t_(1)=0^circ mathrm(C) ] [ P_(1)=10^59 mathrm(~kg) ] [ V= ( const ) ] [ Delta P=3 cdot 10^5 mathrm(~m) ] 4) P= ? (P_(2))/(P_(1))= ? 6) T_(2)= ?

Решения

Ответ