Вопрос
In humans, the absence of sweat glands is a recessive gene. It's located on the X- chromosome. Rh- factor (R) is an autosomal gene. Both parents are healthy and Rh-positive. They have got a baby with the absence of sweat glands and Rh- negative. Solve this task and give diagram. Determine the genotype of each parent and the genotypes and phenotypes of all babies in this family. What is the probability that this couple will have babies suffering from this disorder -the absence of sweat glands'Indicate their genotypes.
Решения
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профессионал · Репетитор 6 лет
Ответ
To solve this problem, we need to determine the genotypes of the parents and the babies based on the given information.1. The absence of sweat glands is a recessive gene located on the X chromosome. Let's denote it as 'a'. Since it is recessive, an individual must have two copies of the recessive allele (aa) to express the trait. Females have two X chromosomes, while males have one X and one Y chromosome.2. The Rh factor is an autosomal gene. Let's denote the Rh-positive allele as 'R' and the Rh-negative allele as 'r'. Since both parents are Rh-positive, they can either be homozygous (RR) or heterozygous (Rr) for the Rh factor.Given that the baby has the absence of sweat glands (aa) and is Rh-negative (rr), we can deduce the following:- The baby must have inherited the recessive allele (a) from both parents.- The baby must have inherited the Rh-negative allele (r) from both parents.Now, let's determine the genotypes of the parents:- Since both parents are healthy and Rh-positive, they can either be RR or Rr for the Rh factor.- To produce a baby with the absence of sweat glands (aa), both parents must be carriers of the recessive allele (Aa).Based on this information, we can create a Punnett square to determine the possible genotypes and phenotypes of the babies:Parent 1: Aa RrParent 2: Aa Rr| | AR | Ar | aR | ar ||---|---|---|---|---|| AR | AARr | AaRr | AaRr | Aarr || Ar | AaRr | Aarr | AaRr | aarr || aR | AaRr | Aarr | aaRr | aarr || ar | AaRr | Aarr | aaRr | aarr |From the Punnett square, we can see that there is a 25% chance (1 out of 4) that the couple will have a baby with the absence of sweat glands (aa) and Rh-negative (rr).Therefore, the probability that this couple will have babies suffering from the absence of sweat glands is 25%.