An electric heater of 800 watts is placed in a vessel containing 5 liters-of water at 20^circ C (C_(w) =4.19kJ/(kgcdot grad) Determine how long it takes for the water to heat to a boiling point of 100^circ C Neglect the heat loss of the vessel to the environment.

To determine how long it takes for the water to heat to a boiling point of , we can use the formula: Where:- is the heat energy required to heat the water- is the mass of the water- is the specific heat capacity of water- is the change in temperatureGiven:- Power of the electric heater = 800 watts- Volume of water = 5 liters- Initial temperature of water = - Final temperature of water = - Specific heat capacity of water ( ) = 4.19 kJ/(kg·°C)First, we need to convert the volume of water to mass. Since the density of water is approximately 1 kg/L, the mass of the water is 5 kg.Now, we can calculate the heat energy required to heat the water: Next, we can calculate the time it takes for the water to heat to the boiling point using the formula: Where:- is the time in seconds- is the heat energy required in joules- is the power of the electric heater in wattsSince 1 kJ = 1000 J, we need to convert the heat energy from kJ to J: Now, we can calculate the time: Therefore, it takes approximately 209.5 seconds for the water to heat to a boiling point of .