5 mathrm(Ca)(mathrm(OH))_(2)+?=mathrm(CaCl)_(2)+? mathrm(Se)_(2)(mathrm(SO)_(4))_(3)+mathrm(BaCl)_(2) arrow

Let's balance the chemical equations step by step.1. For the first equation: To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.First, let's write down the number of atoms for each element on both sides:- Calcium (Ca): 5 on the left, 1 on the right- Oxygen (O): 10 on the left, 2 on the right- Hydrogen (H): 10 on the left, 2 on the right- Chlorine (Cl): 2 on the right, 1 on the leftTo balance the calcium atoms, we need 5 calcium atoms on the right side: Now, let's balance the chlorine atoms. We have 5 calcium atoms on the right side, so we need 5 chlorine atoms on the left side: Finally, let's balance the oxygen and hydrogen atoms. We have 10 oxygen atoms and 10 hydrogen atoms on the left side, so we need 10 oxygen atoms and 10 hydrogen atoms on the right side: So, the balanced equation is: 2. For the second equation: First, let's write down the number of atoms for each element on both sides:- Selenium (Se): 2 on the left, 1 on the right- Sulfur (S): 3 on the left, 1 on the right- Oxygen (O): 12 left, 4 on the right- Barium (Ba): 1 on the left, 1 on the right- Chlorine (Cl): 2 on the left, 1 on the rightTo balance the selenium atoms, we need 2 selenium atoms on the right side: Now, let's balance the sulfur atoms. We have 3 sulfur atoms on the left side, so we need 3 sulfur atoms on the right side: Finally, let's balance the oxygen atoms. We have 12 oxygen atoms on the left side, so we need 12 oxygen atoms on the right side: So, the balanced equation is: Therefore, the balanced equations are: \[ \mathrm{Se}_{2}\left(\mathrm{SO}_{4}\right)_{3} + 3 \mathrm{BaCl}_{2} \rightarrow 2 \mathrm{Se} + 3 \mathrm{BaSO}_{4