5. A 4500 kW steam heat engine has an efficiency of 025. Determine the hourly fuel con- sumption if its calorific value is Q=33MJ/kg

To determine the hourly fuel consumption of the steam heat engine, we can use the formula: Given:- Power Output = 4500 kW- Efficiency = 0.25- Calorific Value = 33 MJ/kg- Time = 1 hourSubstituting the given values into the formula: Therefore, the hourly fuel consumption of the steam heat engine is approximately 545.45 kg.