Вопрос
L, E, F, J, R, B & 2 & 3 & 1 & 7 & & 25 missing frequencies firection of variation e. pus dian and mode tritle deviation the MJ, GM and HN? nic mean of the following grouped data 80-100 & 100-120 38 & 45
Решения
4.3
(272 Голоса)
Максим
Экспертная проверка
профессионал · Репетитор 6 лет
Ответ
To find the mean of the given grouped data, we need to calculate the midpoints of each class interval and then use the formula for the mean of grouped data.Step 1: Calculate the midpoints of each class interval.Midpoint = (Lower limit + Upper limit) / 2For the first class interval, 80-100, the midpoint is (80 + 100) / 2 = 90.For the second class interval, 100-120, the midpoint is (100 + 120) / 2 = 110.Step 2: Multiply the midpoint of each class interval by the frequency of that class.For the first class interval, 80-100, the product is 90 * 38 = 3420.For the second class interval, 100-120, the product is 110 * 45 = 4950.Step 3: Sum up the products obtained in step 2.Sum of products = 3420 + 4950 = 8370.Step 4: Calculate the total frequency.Total frequency = 38 + 45 = 83.Step 5: Calculate the mean of the grouped data.Mean = Sum of products / Total frequencyMean = 8370 / 83 ≈ 101.08.Therefore, the mean of the given grouped data is approximately 101.08.