Вопрос
d) For the process of potassium chlorate decomposition: 2KClO_(3)arrow 2KCl+3O_(2) Delta _(f)H^0_(298)=-89.38kJ/mol and Delta _(r)S_(200)^0=349.51J/moltimes K Calculate Delta G_(298)^0 at 298K and make the conclusion about spontaneity of this reaction.
Решения
4.5
(235 Голоса)
Ольга
Экспертная проверка
эксперт · Репетитор 3 лет
Ответ
To calculate the change in Gibbs free energy (
) for the decomposition of potassium chlorate at 298K, we can use the following equation:
where:
is the change in enthalpy at 298K,
is the temperature in Kelvin, and
is the change in entropy at 298K.Given that
and
, we can substitute these values into the equation:
Since
is negative, the reaction is spontaneous at 298K.