Вопрос
2. Determine the heat transfer coefficient and the linear heat flux in the transverse air flow for a pipe with a diameter of d=25 mm, if its surface temperature is t_(s)= 80^circ C the air temperature is t_(a)=-15^circ C and the wind speed is w=9m/s
Решения
4.6
(230 Голоса)
Леонтий
Экспертная проверка
профессионал · Репетитор 6 лет
Ответ
To determine the heat transfer coefficient and the linear heat flux in the transverse airflow for a pipe, we can use the Dittus-Boelter equation, which is a commonly used empirical correlation for convective heat transfer. The Dittus-Boelter equation is given by:
where:-
is the heat transfer coefficient,-
is the Reynolds number,-
is the Prandtl number,-
is the specific heat capacity of the fluid,-
is the dynamic viscosity of the fluid,-
is the diameter of the pipe.First, we need to calculate the Reynolds number (
) and the Prandtl number (
).The Reynolds number is given by:
where:-
is the wind speed,-
is the diameter of the pipe,-
is the kinematic viscosity of the fluid.The Prandtl number is given by:
where:-
is the specific heat capacity of the fluid,-
is the dynamic viscosity of the fluid,-
is the thermal conductivity of the fluid.Given:-
mm = 0.025 m,-
,-
,-
m/s.Assuming air as the fluid, we can find the properties at the film temperature (
) which is approximately the average of
and
:
Using standard air properties at
:-
J/(kg·K),-
Pa·s,-
m²/s,-
W/(m·K).Now, calculate
:
Next, calculate
:
Now, substitute these values into the Dittus-Boelter equation:
Calculate each term:
\[ h \approx 0.023 \cdot 1.34 \times 10^4 \cdot 0.45 \cdot 7.92 \times 10