Вопрос
1. For titration of 20.00 ml of the analyzed solution containing iron (III) salt. 18.50 ml of EDTA solution with a molar concentration of 0.02500 mol/L and a correction I factor of 0.9800 were spent. Calculate the weight of iron (in grams).
Решения
4.5
(161 Голоса)
Камиль
мастер · Репетитор 5 лет
Ответ
To calculate the weight of iron in the analyzed solution, we need to follow these1. Calculate the moles of EDTA used in the titration.2. Determine the moles of iron (III) salt in the analyzed solution.3. Convert the moles of iron (III) salt to grams.Step 1: Calculate the moles of EDTA used in the titration.Given:Volume of EDTA solution used = 18.50 mlMolar concentration of EDTA solution = 0.02500 mol/LCorrection factor of EDTA solution = 0.9800First, we need to convert the volume of EDTA solution from ml to L:Volume of EDTA solution in L = 18.50 ml / 1000 = 0.01850 LNow, we can calculate the moles of EDTA used in the titration:Moles of EDTA = Molar concentration of EDTA solution × Volume of EDTA solution in LMoles of EDTA = 0.02500 mol/L × 0.01850 LMoles of EDTA = 0.0004625 molStep 2: Determine the moles of iron (III) salt in the analyzed solution.The reaction between EDTA and iron (III) salt is a 1:1 molar ratio. Therefore, the moles (III) salt in the analyzed solution will be equal to the moles of EDTA used in the titration:Moles of iron (III) salt = Moles of EDTAMoles of iron (III) salt = 0.0004625 molStep 3: Convert the moles of iron (III) salt to grams.The molar mass of iron (III) salt (FeCl3) is 162.20 g/mol.Now, we can calculate the weight of iron in the analyzed solution:Weight of iron = Moles of iron (III) salt × Molar mass of iron (III) saltWeight of iron = 0.0004625 mol × 162.20 g/molWeight of iron = 0.0748 gTherefore, the weight of iron in the analyzed solution is 0.0748 grams.