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Equation for the heat flux transferred by heat conduction through a single layer flat wall is: q=K(t_(n1)-t_(12)) q=a(t_(s1)-t_(s2)) q=(lambda )/(delta )(t_(s1)-t_(s2)) q=(delta )/(lambda )(t_(s1)-t_(s2)) q=alpha (t_(f)-t_(s))

Вопрос

Equation for the heat flux transferred by heat conduction through a single layer flat wall is:
q=K(t_(n1)-t_(12))
q=a(t_(s1)-t_(s2))
q=(lambda )/(delta )(t_(s1)-t_(s2))
q=(delta )/(lambda )(t_(s1)-t_(s2))
q=alpha (t_(f)-t_(s))

Equation for the heat flux transferred by heat conduction through a single layer flat wall is: q=K(t_(n1)-t_(12)) q=a(t_(s1)-t_(s2)) q=(lambda )/(delta )(t_(s1)-t_(s2)) q=(delta )/(lambda )(t_(s1)-t_(s2)) q=alpha (t_(f)-t_(s))

Решения

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Радик
Экспертная проверкаЭкспертная проверка
мастер · Репетитор 5 лет

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The correct equation for the heat flux transferred by heat conduction through a single layer flat wall is:<br /><br />$q=\frac {\lambda }{\delta }(t_{s1}-t_{s2})$<br /><br />where:<br />- $q$ is the heat flux (heat transfer per unit area),<br />- $\lambda$ is the thermal conductivity of the material,<br />- $\delta$ is the thickness of the wall,<br />- $t_{s1}$ and $t_{s2}$ are the temperatures on the two sides of the wall.<br /><br />This equation is derived from Fourier's law of heat conduction, which states that the heat flux is proportional to the temperature gradient across the material.
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