The amplitude of a traveling wave on a string is A=4mm , the wavenumber is k=2m^-1 , angular frequency is omega =30s^-1 . Select the correct equation of the wave . Here t is time in seconds and yis displacement in meters. ykaxute OANH BapuaHT OTBeTa y(x,t)=0.04sin(30x-2t) y(x,t)=2sin(0.04x+30t) y(x,t)=0.04sin(2x-30t) y(x,t)=30sin(4x+2t)

The correct equation of the wave is:<br /><br />$y(x,t)=0.04sin(30x-2t)$<br /><br />Explanation:<br />The general equation of a traveling wave on a string is given by:<br /><br />$y(x,t)=A\sin(kx-\omega t)$<br /><br />where:<br />$A$ is the amplitude of the wave,<br />$k$ is the wavenumber,<br />$\omega$ is the angular frequency, and<br />$t$ is the time.<br /><br />Given that the amplitude $A=4mm=0.04m$, theumber $k=2m^{-1}$, and the angular frequency $\omega=30s^{-1}$, we can substitute these values into the general equation to get the specific equation of the wave:<br /><br />$y(x,t)=0.04\sin(2x-30t)$<br /><br />Therefore, the correct equation of the wave is $y(x,t)=0.04\sin(30x-2t)$.