Alternating current obeys the law X=0.5sin2pi t A Determine the numerical values of the basic paran leter s the period is square the frequency is 1 Hz

To determine the numerical values of the basic parameters of the alternating current (AC) given by the equation $X = 0.5 \sin(2\pi t)$, we need to identify the period and frequency.<br /><br />The general form of an AC equation is $X = A \sin(\omega t + \phi)$, where:<br />- $A$ is the amplitude<br />- $\omega$ is the angular frequency<br />- $t$ is the time<br />- $\phi$ is the phase angle<br /><br />In this case, the equation is $X = 0.5 \sin(2\pi t)$, which means:<br />- $A = 0.5$ (amplitude)<br />- $\omega = 2\pi$ (angular frequency)<br /><br />The period ($T$) and frequency ($f$) can be calculated as follows:<br /><br />1. Period ($T$):<br /> The period is the time it takes for the AC to complete one cycle. It can be calculated using the formula:<br /> $T = \frac{2\pi}{\omega}$<br /> Substituting the value of $\omega = 2\pi$, we get:<br /> $T = \frac{2\pi}{2\pi} = 1$ second<br /><br />2. Frequency ($f$):<br /> The frequency is the number of cycles the AC completes per unit time. It can be calculated using the formula:<br /> $f = \frac{1}{T}$<br /> Substituting the value of $T = 1$ second, we get:<br /> $f = \frac{1}{1} = 1$ Hz<br /><br />Therefore, the numerical values of the basic parameters of the alternating current are:<br />- The period is 1 second<br />- The frequency is 1 Hz