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Select the correct equation for normal acceleration a_(n) ykaxknte onuH BapuaHT OTBeTa a_(n)=(v)/(t) where v is velocity and t is time a_(n)=(v^2)/(R) where v is velocity and R is the radius of curvature of the trajectory a_(n)=(R^2)/(v) where v is velocity and R is the radius of curvature of the trajectory

Вопрос

Select the correct equation for normal acceleration
a_(n)
ykaxknte onuH BapuaHT OTBeTa
a_(n)=(v)/(t) where v is velocity and t is
time
a_(n)=(v^2)/(R) where v is velocity and R is
the radius of curvature of the
trajectory
a_(n)=(R^2)/(v) where v is velocity and R is
the radius of curvature of the
trajectory

Select the correct equation for normal acceleration a_(n) ykaxknte onuH BapuaHT OTBeTa a_(n)=(v)/(t) where v is velocity and t is time a_(n)=(v^2)/(R) where v is velocity and R is the radius of curvature of the trajectory a_(n)=(R^2)/(v) where v is velocity and R is the radius of curvature of the trajectory

Решения

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элита · Репетитор 8 лет

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The correct equation for normal acceleration is:<br /><br />$a_{n}=\frac {v^{2}}{R}$ where v is velocity and R is the radius of curvature of the trajectory.<br /><br />Normal acceleration, also known as centripetal acceleration, is the acceleration experienced by an object moving in a circular path. It is directed towards the center of the circle and is responsible for keeping the object in its circular path. The equation for normal acceleration is derived from the formula for centripetal acceleration, which is given by:<br /><br />$a_{n}=\frac {v^{2}}{R}$<br /><br />where v is the velocity of the object and R is the radius of curvature of the trajectory. This equation shows that the normal acceleration is directly proportional to the square of the velocity and inversely proportional to the radius of curvature of the trajectory.
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