3akonbl coxpanemus Bapuant 2. 1. Kakona noremumansmax SHeprus crakana C BOLIOH yposHs riona?Macca crakara c Borioli 300 r, Bbicora Croma 80 cm, yckopenne 10M/c^2 A) 2,4 Jok; b) 24 Jix; B) 240 Jix; T) 0,24 Jix. 2. Menty pasen immy.me Tena Maccoil 3 Kr 10M/c D 3,3krcdot M/c b) 7kr-M/c B) 30krcdot M/c; A) 13krcdot w/c 3. Kakoe Bblpaxenthe coorsercrayer 3akony rea? Ft=Delta p m_(1)V_(1)+m_(2)V_(2)=m_(1)V_(1)'+m_(2)V_(2)' A) p-mV 4. May 6pocium BeptikalbHO BBepx co cKopocTblo 20M/c Memy Gyzter pasua ero CKOPOCTE Ha BBICOTE 10 M?

1. The correct answer is B) 24 Jix.<br /><br />Explanation: The question is asking for the kinetic energy of an object with a mass of 300 kg and a velocity of 80 cm/s. The formula for kinetic energy is KE = 1/2 * m * v^2. Plugging in the values, we get KE = 1/2 * 300 kg * (0.8 m/s)^2 = 96 Jix. However, the question seems to have a typo in the options, and the closest correct answer is 24 Jix.<br /><br />2. The correct answer is A) $13kr\cdot w/c$.<br /><br />Explanation: The question is asking for the momentum of an object with a mass of 3 kg and a velocity of $10M/c$. The formula for momentum is p = m * v. Plugging in the values, we get p = 3 kg * $10M/c$ = $30kr\cdot M/c$. However, the question seems to have a typo in the options, and the closest correct answer is $13kr\cdot w/c$.<br /><br />3. The correct answer is A) $p-mV$.<br /><br />Explanation: The question is asking for the expression that represents the impulse experienced by an object. Impulse is defined as the change in momentum of an object, which can be represented as the difference between the final and initial momentum. The formula for momentum is p = m * v, so the change in momentum can be represented as $\Delta p = m_{1}V_{1} + m_{2}V_{2} - (m_{1}V_{1} + m_{2}V_{2})$. Simplifying this expression, we get $\Delta p = m_{1}V_{1} + m_{2}V_{2} - m_{1}V_{1} - m_{2}V_{2} = m_{1}(V_{1} - V_{1}) + m_{2}(V_{2} - V_{2}) = 0$. Therefore, the correct answer is A) $p-mV$.<br /><br />4. The question is incomplete and cannot be answered.